Move bundled copy of sqlite one level deeper to better separate it...

third_party/sqlite/test/tkt2141.test

Index: third_party/sqlite/test/tkt2141.test
===================================================================
--- third_party/sqlite/test/tkt2141.test	(revision 56608)
+++ third_party/sqlite/test/tkt2141.test	(working copy)
@@ -1,61 +0,0 @@
-# 2007 January 03
-#
-# The author disclaims copyright to this source code.  In place of
-# a legal notice, here is a blessing:
-#
-#    May you do good and not evil.
-#    May you find forgiveness for yourself and forgive others.
-#    May you share freely, never taking more than you give.
-#
-#***********************************************************************
-# This file implements regression tests for SQLite library.
-#
-# This file implements tests to verify that ticket #2141 has been
-# fixed.  
-#
-#
-# $Id: tkt2141.test,v 1.2 2007/09/12 17:01:45 danielk1977 Exp $
-
-set testdir [file dirname $argv0]
-source $testdir/tester.tcl
-
-ifcapable !subquery {
-  finish_test
-  return
-}
-
-do_test tkt2141-1.1 {
-  execsql {
-      CREATE TABLE tab1 (t1_id integer PRIMARY KEY, t1_desc);
-      INSERT INTO tab1 VALUES(1,'rec 1 tab 1');
-      CREATE TABLE tab2 (t2_id integer PRIMARY KEY, t2_id_t1, t2_desc);
-      INSERT INTO tab2 VALUES(1,1,'rec 1 tab 2');
-      CREATE TABLE tab3 (t3_id integer PRIMARY KEY, t3_id_t2, t3_desc);
-      INSERT INTO tab3 VALUES(1,1,'aa');
-      SELECT *
-      FROM tab1 t1 LEFT JOIN tab2 t2 ON t1.t1_id = t2.t2_id_t1
-      WHERE t2.t2_id IN
-           (SELECT t2_id FROM tab2, tab3 ON t2_id = t3_id_t2
-             WHERE t3_id IN (1,2) GROUP BY t2_id);
-  }
-} {1 {rec 1 tab 1} 1 1 {rec 1 tab 2}}
-do_test tkt2141-1.2 {
-  execsql {
-      SELECT *
-      FROM tab1 t1 LEFT JOIN tab2 t2 ON t1.t1_id = t2.t2_id_t1
-      WHERE t2.t2_id IN
-           (SELECT t2_id FROM tab2, tab3 ON t2_id = t3_id_t2
-             WHERE t3_id IN (1,2));
-  }
-} {1 {rec 1 tab 1} 1 1 {rec 1 tab 2}}
-do_test tkt2141-1.3 {
-  execsql {
-      SELECT *
-      FROM tab1 t1 LEFT JOIN tab2 t2
-      WHERE t2.t2_id IN
-           (SELECT t2_id FROM tab2, tab3 ON t2_id = t3_id_t2
-             WHERE t3_id IN (1,2));
-  }
-} {1 {rec 1 tab 1} 1 1 {rec 1 tab 2}}
-
-finish_test