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Issue 10992: Implement $ for non-multiline. (Closed)

Created:
12 years ago by Erik Corry
Modified:
9 years, 7 months ago
CC:
v8-dev
Visibility:
Public.

Description

Implement $ for non-multiline. Committed: http://code.google.com/p/v8/source/detail?r=862

Patch Set 1 #

Unified diffs Side-by-side diffs Delta from patch set Stats (+195 lines, -71 lines) Patch
M src/assembler-irregexp.h View 1 chunk +1 line, -0 lines 0 comments Download
M src/assembler-irregexp.cc View 1 chunk +10 lines, -0 lines 0 comments Download
M src/bytecodes-irregexp.h View 1 chunk +7 lines, -6 lines 0 comments Download
M src/flag-definitions.h View 1 chunk +1 line, -0 lines 0 comments Download
M src/interpreter-irregexp.cc View 1 chunk +7 lines, -0 lines 0 comments Download
M src/jsregexp.h View 3 chunks +10 lines, -6 lines 0 comments Download
M src/jsregexp.cc View 15 chunks +105 lines, -58 lines 1 comment Download
M src/regexp-macro-assembler.h View 1 chunk +1 line, -0 lines 0 comments Download
M src/regexp-macro-assembler-ia32.h View 1 chunk +1 line, -0 lines 0 comments Download
M src/regexp-macro-assembler-ia32.cc View 1 chunk +10 lines, -0 lines 0 comments Download
M src/regexp-macro-assembler-irregexp.h View 1 chunk +1 line, -0 lines 0 comments Download
M src/regexp-macro-assembler-irregexp.cc View 1 chunk +7 lines, -0 lines 0 comments Download
M src/regexp-macro-assembler-tracer.h View 1 chunk +1 line, -0 lines 0 comments Download
M src/regexp-macro-assembler-tracer.cc View 1 chunk +12 lines, -0 lines 0 comments Download
M test/cctest/test-regexp.cc View 1 chunk +1 line, -1 line 0 comments Download
M test/mjsunit/regexp.js View 1 chunk +20 lines, -0 lines 0 comments Download

Messages

Total messages: 2 (0 generated)
Erik Corry
12 years ago (2008-11-28 08:11:34 UTC) #1
Christian Plesner Hansen
12 years ago (2008-11-28 08:44:53 UTC) #2
Stv!

http://codereview.chromium.org/10992/diff/1/16
File src/jsregexp.cc (right):

http://codereview.chromium.org/10992/diff/1/16#newcode2342
Line 2342: // TODO(erikcorry): A back reference has to have two successors (by
default
I wonder if maybe we always have to propagate to the on-failure continuation. 
In most cases it will be a backtrack node and it won't matter, but it may not be
and in that case we must propagate.

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