Chromium Code Reviews
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| 1 /* This Source Code Form is subject to the terms of the Mozilla Public | |
| 2 * License, v. 2.0. If a copy of the MPL was not distributed with this | |
| 3 * file, You can obtain one at http://mozilla.org/MPL/2.0/. */ | |
| 4 | |
| 5 #ifdef FREEBL_NO_DEPEND | |
| 6 #include "stubs.h" | |
| 7 #endif | |
| 8 #include "blapit.h" | |
| 9 #include "blapii.h" | |
| 10 #include "cts.h" | |
| 11 #include "secerr.h" | |
| 12 | |
| 13 struct CTSContextStr { | |
| 14 freeblCipherFunc cipher; | |
| 15 void *context; | |
| 16 unsigned char iv[MAX_BLOCK_SIZE]; | |
| 17 }; | |
| 18 | |
| 19 CTSContext * | |
| 20 CTS_CreateContext(void *context, freeblCipherFunc cipher, | |
| 21 const unsigned char *iv, unsigned int blocksize) | |
| 22 { | |
| 23 CTSContext *cts; | |
| 24 | |
| 25 cts = PORT_ZNew(CTSContext); | |
| 26 if (cts == NULL) { | |
| 27 return NULL; | |
| 28 } | |
| 29 PORT_Memcpy(cts->iv, iv, blocksize); | |
| 30 cts->cipher = cipher; | |
| 31 cts->context = context; | |
| 32 return cts; | |
| 33 } | |
| 34 | |
| 35 void | |
| 36 CTS_DestroyContext(CTSContext *cts, PRBool freeit) | |
| 37 { | |
| 38 if (freeit) { | |
| 39 PORT_Free(cts); | |
| 40 } | |
| 41 } | |
| 42 | |
| 43 /* | |
| 44 * See addemdum to NIST SP 800-38A | |
| 45 * Generically handle cipher text stealing. Basically this is doing CBC | |
| 46 * operations except someone can pass us a partial block. | |
| 47 * | |
| 48 * Output Order: | |
| 49 * CS-1: C1||C2||C3..Cn-1(could be partial)||Cn (NIST) | |
| 50 * CS-2: pad == 0 C1||C2||C3...Cn-1(is full)||Cn (Schneier) | |
| 51 * CS-2: pad != 0 C1||C2||C3...Cn||Cn-1(is partial)(Schneier) | |
| 52 * CS-3: C1||C2||C3...Cn||Cn-1(could be partial) (Kerberos) | |
| 53 * | |
| 54 * The characteristics of these three options: | |
| 55 * - NIST & Schneier (CS-1 & CS-2) are identical to CBC if there are no | |
| 56 * partial blocks on input. | |
| 57 * - Scheier and Kerberos (CS-2 and CS-3) have no embedded partial blocks, | |
| 58 * which make decoding easier. | |
| 59 * - NIST & Kerberos (CS-1 and CS-3) have consistant block order independent | |
| 60 * of padding. | |
| 61 * | |
| 62 * PKCS #11 did not specify which version to implement, but points to the NIST | |
| 63 * spec, so this code implements CTS-CS-1 from NIST. | |
| 64 * | |
| 65 * To convert the returned buffer to: | |
| 66 * CS-2 (Schneier): do | |
| 67 * unsigned char tmp[MAX_BLOCK_SIZE]; | |
| 68 * pad = *outlen % blocksize; | |
| 69 * if (pad) { | |
| 70 * memcpy(tmp, outbuf+*outlen-blocksize, blocksize); | |
| 71 * memcpy(outbuf+*outlen-pad,outbuf+*outlen-blocksize-pad, pad); | |
| 72 * memcpy(outbuf+*outlen-blocksize-pad, tmp, blocksize); | |
| 73 * } | |
| 74 * CS-3 (Kerberos): do | |
| 75 * unsigned char tmp[MAX_BLOCK_SIZE]; | |
| 76 * pad = *outlen % blocksize; | |
| 77 * if (pad == 0) { | |
| 78 * pad = blocksize; | |
| 79 * } | |
| 80 * memcpy(tmp, outbuf+*outlen-blocksize, blocksize); | |
| 81 * memcpy(outbuf+*outlen-pad,outbuf+*outlen-blocksize-pad, pad); | |
| 82 * memcpy(outbuf+*outlen-blocksize-pad, tmp, blocksize); | |
| 83 */ | |
| 84 SECStatus | |
| 85 CTS_EncryptUpdate(CTSContext *cts, unsigned char *outbuf, | |
| 86 unsigned int *outlen, unsigned int maxout, | |
| 87 const unsigned char *inbuf, unsigned int inlen, | |
| 88 unsigned int blocksize) | |
| 89 { | |
| 90 unsigned char lastBlock[MAX_BLOCK_SIZE]; | |
| 91 unsigned int tmp; | |
| 92 int fullblocks; | |
| 93 int written; | |
| 94 SECStatus rv; | |
| 95 | |
| 96 if (inlen < blocksize) { | |
| 97 PORT_SetError(SEC_ERROR_INPUT_LEN); | |
| 98 return SECFailure; | |
| 99 } | |
| 100 | |
| 101 if (maxout < inlen) { | |
| 102 *outlen = inlen; | |
| 103 PORT_SetError(SEC_ERROR_OUTPUT_LEN); | |
| 104 return SECFailure; | |
| 105 } | |
| 106 fullblocks = (inlen/blocksize)*blocksize; | |
| 107 rv = (*cts->cipher)(cts->context, outbuf, outlen, maxout, inbuf, | |
| 108 fullblocks, blocksize); | |
| 109 if (rv != SECSuccess) { | |
| 110 return SECFailure; | |
| 111 } | |
| 112 inbuf += fullblocks; | |
| 113 inlen -= fullblocks; | |
| 114 if (inlen == 0) { | |
| 115 return SECSuccess; | |
| 116 } | |
| 117 written = *outlen - (blocksize - inlen); | |
| 118 outbuf += written; | |
| 119 maxout -= written; | |
| 120 | |
| 121 /* | |
| 122 * here's the CTS magic, we pad our final block with zeros, | |
| 123 * then do a CBC encrypt. CBC will xor our plain text with | |
| 124 * the previous block (Cn-1), capturing part of that block (Cn-1**) as it | |
| 125 * xors with the zero pad. We then write this full block, overwritting | |
| 126 * (Cn-1**) in our buffer. This allows us to have input data == output | |
| 127 * data since Cn contains enough information to reconver Cn-1** when | |
| 128 * we decrypt (at the cost of some complexity as you can see in decrypt | |
| 129 * below */ | |
| 130 PORT_Memcpy(lastBlock, inbuf, inlen); | |
| 131 if (blocksize - inlen != 0) { | |
|
Ryan Sleevi
2012/09/17 22:57:26
Is it worth adding the explicit parenthesis?
if ((
wtc
2012/09/18 01:03:40
I usually don't add parentheses in this kind of ex
| |
| 132 PORT_Memset(lastBlock + inlen, 0, blocksize - inlen); | |
| 133 } | |
| 134 rv = (*cts->cipher)(cts->context, outbuf, &tmp, maxout, lastBlock, | |
| 135 blocksize, blocksize); | |
| 136 PORT_Memset(lastBlock, 0, blocksize); | |
| 137 return rv; | |
| 138 } | |
| 139 | |
| 140 | |
| 141 #define XOR_BLOCK(x,y,count) for(i=0; i < count; i++) x[i] = x[i] ^ y[i] | |
| 142 | |
| 143 /* | |
| 144 * See addemdum to NIST SP 800-38A | |
| 145 * Decrypt, Expect CS-1: input. See the comment on the encrypt side | |
| 146 * to understand what CS-2 and CS-3 mean. | |
| 147 * | |
| 148 * To convert the input buffer to CS-1 from ... | |
| 149 * CS-2 (Schneier): do | |
| 150 * unsigned char tmp[MAX_BLOCK_SIZE]; | |
| 151 * pad = inlen % blocksize; | |
| 152 * if (pad) { | |
| 153 * memcpy(tmp, inbuf+inlen-blocksize-pad, blocksize); | |
| 154 * memcpy(inbuf+inlen-blocksize-pad,inbuf+inlen-pad, pad); | |
| 155 * memcpy(inbuf+inlen-blocksize, tmp, blocksize); | |
| 156 * } | |
| 157 * CS-3 (Kerberos): do | |
| 158 * unsigned char tmp[MAX_BLOCK_SIZE]; | |
| 159 * pad = inlen % blocksize; | |
| 160 * if (pad == 0) { | |
| 161 * pad = blocksize; | |
| 162 * } | |
| 163 * memcpy(tmp, inbuf+inlen-blocksize-pad, blocksize); | |
| 164 * memcpy(inbuf+inlen-blocksize-pad,inbuf+inlen-pad, pad); | |
| 165 * memcpy(inbuf+inlen-blocksize, tmp, blocksize); | |
| 166 */ | |
| 167 SECStatus | |
| 168 CTS_DecryptUpdate(CTSContext *cts, unsigned char *outbuf, | |
| 169 unsigned int *outlen, unsigned int maxout, | |
| 170 const unsigned char *inbuf, unsigned int inlen, | |
| 171 unsigned int blocksize) | |
| 172 { | |
| 173 unsigned char *Pn; | |
| 174 unsigned char Cn_2[MAX_BLOCK_SIZE]; /* block Cn-2 */ | |
| 175 unsigned char Cn_1[MAX_BLOCK_SIZE]; /* block Cn-1 */ | |
| 176 unsigned char Cn[MAX_BLOCK_SIZE]; /* block Cn */ | |
| 177 unsigned char lastBlock[MAX_BLOCK_SIZE]; | |
| 178 const unsigned char *tmp; | |
| 179 unsigned int tmpLen; | |
| 180 int fullblocks, pad, i; | |
| 181 SECStatus rv; | |
| 182 | |
| 183 if (inlen < blocksize) { | |
| 184 PORT_SetError(SEC_ERROR_INPUT_LEN); | |
| 185 return SECFailure; | |
| 186 } | |
| 187 | |
| 188 if (maxout < inlen) { | |
| 189 *outlen = inlen; | |
| 190 PORT_SetError(SEC_ERROR_OUTPUT_LEN); | |
| 191 return SECFailure; | |
| 192 } | |
| 193 | |
| 194 fullblocks = (inlen/blocksize)*blocksize; | |
| 195 | |
| 196 /* even though we expect the input to be CS-1, CS-2 is easier to parse, | |
| 197 * so convert to CS-2 immediately. NOTE: this is the same code as in | |
| 198 * the comment for encrypt. NOTE2: since we can't modify inbuf unless | |
| 199 * inbuf and outbuf overlap, just copy inbuf to outbuf and modify it there | |
| 200 */ | |
| 201 pad = blocksize - (fullblocks - inlen); | |
|
wtc
2012/09/18 01:03:40
pad = blocksize + (inlen - fullblocks); // avoid
| |
| 202 if (pad != blocksize) { | |
| 203 if (inbuf != outbuf) { | |
| 204 memcpy(outbuf, inbuf, inlen); | |
| 205 /* keep the names so we logically know how we are using the | |
| 206 * buffers */ | |
| 207 inbuf = outbuf; | |
| 208 } | |
| 209 memcpy(lastBlock, inbuf+inlen-blocksize-pad, blocksize); | |
| 210 /* we know inbuf == outbuf now, inbuf is declared const and can't | |
| 211 * be the target, so use outbuf for the target here */ | |
| 212 memcpy(outbuf+inlen-blocksize-pad, inbuf+inlen-pad, pad); | |
| 213 memcpy(outbuf+inlen-blocksize, lastBlock, blocksize); | |
|
wtc
2012/09/18 01:03:40
BUG: you are doing the opposite conversion (from C
| |
| 214 } | |
| 215 /* save the previous to last block so we can undo the misordered chaining*/ | |
| 216 tmp = (fullblocks < blocksize*2) ? cts->iv : | |
| 217 inbuf+fullblocks-blocksize*2; | |
| 218 PORT_Memcpy(Cn_2, tmp, blocksize); | |
| 219 PORT_Memcpy(Cn, inbuf+fullblocks-blocksize, blocksize); | |
| 220 rv = (*cts->cipher)(cts->context, outbuf, outlen, maxout, inbuf, | |
| 221 fullblocks, blocksize); | |
| 222 if (rv != SECSuccess) { | |
| 223 return SECFailure; | |
| 224 } | |
| 225 inbuf += fullblocks; | |
| 226 inlen -= fullblocks; | |
| 227 if (inlen == 0) { | |
| 228 return SECSuccess; | |
| 229 } | |
| 230 outbuf += fullblocks; | |
| 231 maxout -= fullblocks; | |
| 232 | |
| 233 /* recover the stolen text */ | |
| 234 PORT_Memset(lastBlock, 0, blocksize); | |
| 235 PORT_Memcpy(lastBlock, inbuf, inlen); | |
| 236 PORT_Memcpy(Cn_1, inbuf, inlen); | |
| 237 Pn = outbuf-blocksize; | |
| 238 /* inbuf points to Cn-1* in the input buffer */ | |
| 239 /* NOTE: below there are 2 sections marked "make up for the out of order | |
| 240 * cbc decryption". You may ask, what is going on here. | |
| 241 * Short answer: CBC automatically xors the plain text with the previous | |
| 242 * encrypted block. We are decrypting the last 2 blocks out of order, so | |
| 243 * we have to 'back out' the decrypt xor and 'add back' the encrypt xor. | |
| 244 * Long answer: When we encrypted, we encrypted as follows: | |
| 245 * Pn-2, Pn-1, (Pn || 0), but on decryption we can't | |
| 246 * decrypt Cn-1 until we decrypt Cn because part of Cn-1 is stored in | |
| 247 * Cn (see below). So above we decrypted all the full blocks: | |
| 248 * Cn-2, Cn, | |
| 249 * to get: | |
| 250 * Pn-2, Pn, Except that Pn is not yet corect. On encrypt, we | |
| 251 * xor'd Pn || 0 with Cn-1, but on decrypt we xor'd it with Cn-2 | |
| 252 * To recover Pn, we xor the block with Cn-1* || 0 (in last block) and | |
| 253 * Cn-2 to get Pn || Cn-1**. Pn can then be written to the output buffer | |
| 254 * and we can now reunite Cn-1. With the full Cn-1 we can decrypt it, | |
| 255 * but now decrypt is going to xor the decrypted data with Cn instead of | |
| 256 * Cn-2. xoring Cn and Cn-2 restores the original Pn-1 and we can now | |
| 257 * write that oout to the buffer */ | |
| 258 | |
| 259 /* make up for the out of order CBC decryption */ | |
| 260 XOR_BLOCK(lastBlock, Cn_2, blocksize); | |
| 261 XOR_BLOCK(lastBlock, Pn, blocksize); | |
| 262 /* last buf now has Pn || Cn-1**, copy out Pn */ | |
| 263 PORT_Memcpy(outbuf, lastBlock, inlen); | |
| 264 *outlen += inlen; | |
| 265 /* copy Cn-1* into last buf to recover Cn-1 */ | |
| 266 PORT_Memcpy(lastBlock, Cn-1, inlen); | |
| 267 /* note: because Cn and Cn-1 were out of order, our pointer to Pn also | |
| 268 * points to where Pn-1 needs to reside. From here on out read Pn in | |
| 269 * the code as really Pn-1. */ | |
| 270 rv = (*cts->cipher)(cts->context, Pn, &tmpLen, blocksize, lastBlock, | |
| 271 blocksize, blocksize); | |
| 272 if (rv != SECSuccess) { | |
| 273 return SECFailure; | |
| 274 } | |
| 275 /* make up for the out of order CBC decryption */ | |
| 276 XOR_BLOCK(Pn, Cn_2, blocksize); | |
| 277 XOR_BLOCK(Pn, Cn, blocksize); | |
| 278 /* reset iv to Cn */ | |
| 279 PORT_Memcpy(cts->iv, Cn, blocksize); | |
| 280 /* This makes Cn the last block for the next decrypt operation, which | |
| 281 * matches the encrypt. We don't care about the contexts of last block, | |
| 282 * only the side effect of setting the internal IV */ | |
| 283 (void) (*cts->cipher)(cts->context, lastBlock, &tmpLen, blocksize, Cn, | |
|
wtc
2012/09/18 01:03:40
Should we check the return value?
| |
| 284 blocksize, blocksize); | |
| 285 /* clear last block. At this point last block contains Pn xor Cn_1 xor | |
| 286 * Cn_2, both of with an attacker would know, so we need to clear this | |
| 287 * buffer out */ | |
| 288 PORT_Memset(lastBlock, 0, blocksize); | |
| 289 /* Cn, Cn_1, and Cn_2 have encrypted data, so no need to clear them */ | |
| 290 return SECSuccess; | |
| 291 } | |
| 292 | |
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