Fix bug http://code.google.com/p/v8/issues/detail?id=659. Move the limits che...

src/macros.py

 # Copyright 2006-2009 the V8 project authors. All rights reserved.
 # Redistribution and use in source and binary forms, with or without
 # modification, are permitted provided that the following conditions are
 # met:
 #
 #     * Redistributions of source code must retain the above copyright
 #       notice, this list of conditions and the following disclaimer.
 #     * Redistributions in binary form must reproduce the above
 #       copyright notice, this list of conditions and the following
 #       disclaimer in the documentation and/or other materials provided
@@ skipping 110 matching lines @@
 python macro CHAR_CODE(str) = ord(str[1]);
 
 # Constants used on an array to implement the properties of the RegExp object.
 const REGEXP_NUMBER_OF_CAPTURES = 0;
 const REGEXP_FIRST_CAPTURE = 3;
 
 # We can't put macros in macros so we use constants here.
 # REGEXP_NUMBER_OF_CAPTURES
 macro NUMBER_OF_CAPTURES(array) = ((array)[0]);
 
+# Limit according to ECMA 262 15.9.1.1
+const MAX_TIME_MS = 8640000000000000;
+
 # Gets the value of a Date object. If arg is not a Date object
 # a type error is thrown.
 macro DATE_VALUE(arg) = (%_ClassOf(arg) === 'Date' ? %_ValueOf(arg) : ThrowDateTypeError());
 macro DAY(time) = ($floor(time / 86400000));
 macro MONTH_FROM_TIME(time) = (MonthFromTime(time));
 macro DATE_FROM_TIME(time) = (DateFromTime(time));
 macro YEAR_FROM_TIME(time) = (YearFromTime(time));
 macro HOUR_FROM_TIME(time) = (Modulo($floor(time / 3600000), 24));
 macro MIN_FROM_TIME(time) = (Modulo($floor(time / 60000), 60));
 macro SEC_FROM_TIME(time) = (Modulo($floor(time / 1000), 60));
 macro MS_FROM_TIME(time) = (Modulo(time, 1000));
 
 # Last input and last subject of regexp matches.
 macro LAST_SUBJECT(array) = ((array)[1]);
 macro LAST_INPUT(array) = ((array)[2]);
 
 # REGEXP_FIRST_CAPTURE
 macro CAPTURE(index) = (3 + (index));
 const CAPTURE0 = 3;
 const CAPTURE1 = 4;